Convert from dBW
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dBW with Z = Ω
\( dBW + 10 \cdot log_{10}(Z) + 120 =\)
dBμV
\( dBW + 10 \cdot log_{10}(Z) + 60 =\)
dBmV
\( dBW + 10 \cdot log_{10}(Z) =\)
dBV
\( dBW - 10 \cdot log_{10}(Z) + 120 =\)
dBμA
\( dBW - 10 \cdot log_{10}(Z) + 60 =\)
dBmA
\( dBW - 10 \cdot log_{10}(Z) =\)
dBA
\( dBW + 120 = \)
dBpW
\( dBW + 30 = \)
dBm
\( \sqrt{10^{dBW/10} \cdot Z} \cdot 10^6 = \)
μV
\( \sqrt{10^{dBW/10} \cdot Z} \cdot 10^3 = \)
mV
\( \sqrt{10^{dBW/10} \cdot Z} = \)
V
\( \sqrt{ \frac{10^{dBW/10}} {Z}} \cdot 10^6 = \)
μA
\( \sqrt{ \frac{10^{dBW/10}} {Z}} \cdot 10^3 = \)
mA
\( \sqrt{ \frac{10^{dBW/10}} {Z}} = \)
A
\( 10^{(dBW+120)/10} = \)
pW
\( 10^{(dBW+30)/10} = \)
mW
\( 10^{dBW/10} = \)
W