Convert from dBmA

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Convert from
dBmA with Z = Ω  
 
\(dBmA + 20 \cdot log_{10}(Z)+60 =\)
dBμV
\(dBmA + 20 \cdot log_{10}(Z)=\)
dBmV
\(dBmA+20 \cdot log_{10}(Z)-60=\)
dBV
\( dBmA+60= \)
dBμA
\( dBmA-60= \)
dBA
\( dBmA+10 \cdot log_{10}(Z)+60= \)
dBpW
\( dBmA+10 \cdot log_{10}(Z)-30= \)
dBm
\( dBmA+10 \cdot log_{10}(Z)-60= \)
dBW
 
\( 10^{(dBmA+20 \cdot log_{10}(Z)+60)/20}= \)
μV
\( 10^{(dBmA+20 \cdot log_{10}(Z))/20}= \)
mV
\( 10^{(dBmA+20 \cdot log_{10}(Z)-60)/20}= \)
V
\( 10^{(dBmA+60)/20}= \)
μA
\( 10^{dBmA/20}= \)
mA
\( 10^{(dBmA-60)/20}= \)
A
\( 10^{(dBμA+20 \cdot log_{10}(Z)+60)/10}= \)
pW
\( 10^{(dBμA+20 \cdot log_{10}(Z)-30)/10}= \)
mW
\( 10^{(dBμA+20 \cdot log_{10}(Z)-60)/10}= \)
W